(3x+7)(2x^2-3x+1)=0

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Solution for (3x+7)(2x^2-3x+1)=0 equation: 


Simplifying
(3x + 7)(2x2 + -3x + 1) = 0

Reorder the terms:
(7 + 3x)(2x2 + -3x + 1) = 0

Reorder the terms:
(7 + 3x)(1 + -3x + 2x2) = 0

Multiply (7 + 3x) * (1 + -3x + 2x2)
(7(1 + -3x + 2x2) + 3x * (1 + -3x + 2x2)) = 0
((1 * 7 + -3x * 7 + 2x2 * 7) + 3x * (1 + -3x + 2x2)) = 0
((7 + -21x + 14x2) + 3x * (1 + -3x + 2x2)) = 0
(7 + -21x + 14x2 + (1 * 3x + -3x * 3x + 2x2 * 3x)) = 0
(7 + -21x + 14x2 + (3x + -9x2 + 6x3)) = 0

Reorder the terms:
(7 + -21x + 3x + 14x2 + -9x2 + 6x3) = 0

Combine like terms: -21x + 3x = -18x
(7 + -18x + 14x2 + -9x2 + 6x3) = 0

Combine like terms: 14x2 + -9x2 = 5x2
(7 + -18x + 5x2 + 6x3) = 0

Solving
7 + -18x + 5x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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